![Sketch the region of integration for the following integral: \int_{0}^{\sqrt \pi} \int_{y^2}^{\pi} \sqrt x \cos(x) dx dy | Homework.Study.com Sketch the region of integration for the following integral: \int_{0}^{\sqrt \pi} \int_{y^2}^{\pi} \sqrt x \cos(x) dx dy | Homework.Study.com](https://homework.study.com/cimages/multimages/16/hgtdiuhgtr1684798413435168836.png)
Sketch the region of integration for the following integral: \int_{0}^{\sqrt \pi} \int_{y^2}^{\pi} \sqrt x \cos(x) dx dy | Homework.Study.com
![geometry - there is any relation between $\pi$, $\sqrt{2}$ or a generic polygon? - Mathematics Stack Exchange geometry - there is any relation between $\pi$, $\sqrt{2}$ or a generic polygon? - Mathematics Stack Exchange](https://i.stack.imgur.com/pFBV3.png)
geometry - there is any relation between $\pi$, $\sqrt{2}$ or a generic polygon? - Mathematics Stack Exchange
![The region bounded by the x-axis and the graph of y = cos x2 on the interval (0, sqrt pi/2) is revolved about the y-axis. Find the volume of the resulting solid. The region bounded by the x-axis and the graph of y = cos x2 on the interval (0, sqrt pi/2) is revolved about the y-axis. Find the volume of the resulting solid.](https://homework.study.com/cimages/multimages/16/capture_23286295300575973365.png)
The region bounded by the x-axis and the graph of y = cos x2 on the interval (0, sqrt pi/2) is revolved about the y-axis. Find the volume of the resulting solid.
![trigonometry - Deriving $\psi_1(x)=\frac{3\sqrt\pi}{2}\phi_0(x) + \frac{7\ sqrt\pi}{4\sqrt2} \phi_1(x) - \frac{\sqrt\pi}{2\sqrt2} \phi_2(x)...$ - Mathematics Stack Exchange trigonometry - Deriving $\psi_1(x)=\frac{3\sqrt\pi}{2}\phi_0(x) + \frac{7\ sqrt\pi}{4\sqrt2} \phi_1(x) - \frac{\sqrt\pi}{2\sqrt2} \phi_2(x)...$ - Mathematics Stack Exchange](https://i.stack.imgur.com/CByBe.jpg)