cos{cos^(- 1)((-sqrt(3))/2)+pi/6}` - YouTube
BioMath: Trigonometric Functions
The value of sin^(-1)(-sqrt(3)/2)\ is: (A) (-pi)/3 (B) (-2pi)/3 (C) (4pi)/3 (D) (5pi)/3
![Use the figure below to find all angles between 0 and 2\pi satisfying the given condition. (Enter your answers as a comma-separated list.) tan \theta = \sqrt{3}/3 \theta = [{Blank}]. | Homework.Study.com](https://homework.study.com/cimages/multimages/16/capture8949362853141012552.png "Use the figure below to find all angles between 0 and 2\pi satisfying the given condition. (Enter your answers as a comma-separated list.) tan \theta = \sqrt{3}/3 \theta = [{Blank}]. | Homework.Study.com")
Use the figure below to find all angles between 0 and 2\pi satisfying the given condition. (Enter your answers as a comma-separated list.) tan \theta = \sqrt{3}/3 \theta = [{Blank}]. | Homework.Study.com
SOLVED: tan x=- 4 /3 , pi 2 < alpha< pi; cos beta= sqrt 3/ 2 ,0< beta< pi 2
SOLVED: arcsin(- sqrt3/2) Please explain in detail, thank you! Can you also explain why it is -pi/3, instead of -5pi/3?
![math]\sqrt{2} + \sqrt{3} \approx \pi[/math]. Does this have any significance or is it just a coincidence? - Quora](https://qph.cf2.quoracdn.net/main-qimg-b8a5bae86fa22559591328b70b43c66b.webp "math]\sqrt{2} + \sqrt{3} \approx \pi[/math]. Does this have any significance or is it just a coincidence? - Quora")
math]\sqrt{2} + \sqrt{3} \approx \pi[/math]. Does this have any significance or is it just a coincidence? - Quora
SOLUTION: Evaluate the six trigonometric function of: s=2π/3. Show your solution. 1. sin s = cos s = tan s = cot s = csc s = sec s =
=\frac{\sqrt{3}}{2}&line2=\mathrm{Solution:\:}x=\frac{%CF%80}{30}%2B\frac{2%CF%80n}{5},x=\frac{11%CF%80}{30}%2B\frac{2%CF%80n}{5} "cos(5x)=(sqrt(3))/2")
cos(5x)=(sqrt(3))/2
=\frac{\sqrt{3}}{2}&line2=\mathrm{Solution:\:}x=2%CF%80n%2B\frac{5%CF%80}{12},x=2%CF%80n%2B\frac{25%CF%80}{12} "cos(x-pi/4)=(sqrt(3))/2")
cos(x-pi/4)=(sqrt(3))/2
math]\sqrt{2} + \sqrt{3} \approx \pi[/math]. Does this have any significance or is it just a coincidence? - Quora
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![Evaluate : `sin[pi/2 - sin^(-1) (- sqrt(3)/2)]` - YouTube](https://i.ytimg.com/vi/7vseqNL7IMg/maxresdefault.jpg "Evaluate : `sin[pi/2 - sin^(-1) (- sqrt(3)/2)]` - YouTube")
Evaluate : `sin[pi/2 - sin^(-1) (- sqrt(3)/2)]` - YouTube
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