![Trigonometric equations] When solving this one algebraically I get no real solutions but drawing it I see two solutions?? : r/learnmath Trigonometric equations] When solving this one algebraically I get no real solutions but drawing it I see two solutions?? : r/learnmath](https://external-preview.redd.it/UjrRWVnwLqOb2pT96wjoAMtfwjWU4C1K_ieRb7_UkIM.jpg?auto=webp&s=99eb03d5c57ab15b9663c8ae393ed97d94c3261c)
Trigonometric equations] When solving this one algebraically I get no real solutions but drawing it I see two solutions?? : r/learnmath
![Mathematics | Free Full-Text | A Review of Energy and Sustainability KPI-Based Monitoring and Control Methodologies on WWTPs Mathematics | Free Full-Text | A Review of Energy and Sustainability KPI-Based Monitoring and Control Methodologies on WWTPs](https://www.mdpi.com/mathematics/mathematics-11-00173/article_deploy/html/images/mathematics-11-00173-g001.png)
Mathematics | Free Full-Text | A Review of Energy and Sustainability KPI-Based Monitoring and Control Methodologies on WWTPs
![f (x) = [ 2x ]sin 3pi x and f ( k^ + ) = lambda kpi (- 1 )^k (where [.]denotes the greatest integer function and k ∈ N ), then find the value of lambda . f (x) = [ 2x ]sin 3pi x and f ( k^ + ) = lambda kpi (- 1 )^k (where [.]denotes the greatest integer function and k ∈ N ), then find the value of lambda .](https://haygot.s3.amazonaws.com/questions/1180933_1113344_ans_ec20bfc403534a058686cd40dfdc3a2e.jpeg)
f (x) = [ 2x ]sin 3pi x and f ( k^ + ) = lambda kpi (- 1 )^k (where [.]denotes the greatest integer function and k ∈ N ), then find the value of lambda .
![algebra precalculus - Unclear why the highest argument value for cosine function $\cos(x+\frac{\pi}{4})$ is $\frac{\pi}{2}$ - Mathematics Stack Exchange algebra precalculus - Unclear why the highest argument value for cosine function $\cos(x+\frac{\pi}{4})$ is $\frac{\pi}{2}$ - Mathematics Stack Exchange](https://i.stack.imgur.com/TONmm.png)
algebra precalculus - Unclear why the highest argument value for cosine function $\cos(x+\frac{\pi}{4})$ is $\frac{\pi}{2}$ - Mathematics Stack Exchange
![Let `z_k = cos(2kpi/10)+isin(2kpi/10); k=1,2,34,...,9` (A) For each `z_k` there exists a `z_j`... - YouTube Let `z_k = cos(2kpi/10)+isin(2kpi/10); k=1,2,34,...,9` (A) For each `z_k` there exists a `z_j`... - YouTube](https://i.ytimg.com/vi/X7nITCeXogI/maxresdefault.jpg)
Let `z_k = cos(2kpi/10)+isin(2kpi/10); k=1,2,34,...,9` (A) For each `z_k` there exists a `z_j`... - YouTube
Equation sin 7x + cos 2x = 2 Solution is A) x=(2kpi)/7 + 3pi/14,kI B) x=npi + pi/4 , n I C)x= 2npi + pi/2 ,n I D)none of these
![Can someone explain to me why are we adding 2kpi when we are doing zeros for sin and cos, but adding kpi - Brainly.com Can someone explain to me why are we adding 2kpi when we are doing zeros for sin and cos, but adding kpi - Brainly.com](https://us-static.z-dn.net/files/d6b/942675e069ac7ba56c7b1c92a4c48699.jpg)
Can someone explain to me why are we adding 2kpi when we are doing zeros for sin and cos, but adding kpi - Brainly.com
![đk x $\neq$ $\pi$/3 + k $\pi$ x $\neq$ $\pi$ /2 +k $\pi$ pt có nghiệm x= ± pi/3 + k2pi, x =k2pi , x=pi/2+k2pi đối chiếu điều kiện với ạ vẽ đk x $\neq$ $\pi$/3 + k $\pi$ x $\neq$ $\pi$ /2 +k $\pi$ pt có nghiệm x= ± pi/3 + k2pi, x =k2pi , x=pi/2+k2pi đối chiếu điều kiện với ạ vẽ](https://img.hoidap247.com/picture/answer/20191001/large_1569946443875.jpg)